#CCBCHBAHAI0000130. Điền mảng III (Array Fill III)
Điền mảng III (Array Fill III)
Array Fill III
Source: beecrowd
Version: Phuoc Hung OJ Extended
Problem Statement
Given a real number , construct a real-valued array containing exactly elements using
Print every array element with exactly four digits after the decimal point.
Input
One line contains a double-precision real number written with four digits after the decimal point.
Output
Print exactly lines. For each from through , print N[i] = Y, where is formatted with exactly four digits after the decimal point.
Subtasks
Subtask 1 (100 points): . This magnitude bound is part of the Phuoc Hung OJ data configuration; the recurrence and output format are unchanged.
Examples
Input
200.0000
Output
N[0] = 200.0000
N[1] = 100.0000
N[2] = 50.0000
N[3] = 25.0000
N[4] = 12.5000
N[5] = 6.2500
N[6] = 3.1250
N[7] = 1.5625
N[8] = 0.7812
N[9] = 0.3906
N[10] = 0.1953
N[11] = 0.0977
N[12] = 0.0488
N[13] = 0.0244
N[14] = 0.0122
N[15] = 0.0061
N[16] = 0.0031
N[17] = 0.0015
N[18] = 0.0008
N[19] = 0.0004
N[20] = 0.0002
N[21] = 0.0001
N[22] = 0.0000
N[23] = 0.0000
N[24] = 0.0000
N[25] = 0.0000
N[26] = 0.0000
N[27] = 0.0000
N[28] = 0.0000
N[29] = 0.0000
N[30] = 0.0000
N[31] = 0.0000
N[32] = 0.0000
N[33] = 0.0000
N[34] = 0.0000
N[35] = 0.0000
N[36] = 0.0000
N[37] = 0.0000
N[38] = 0.0000
N[39] = 0.0000
N[40] = 0.0000
N[41] = 0.0000
N[42] = 0.0000
N[43] = 0.0000
N[44] = 0.0000
N[45] = 0.0000
N[46] = 0.0000
N[47] = 0.0000
N[48] = 0.0000
N[49] = 0.0000
N[50] = 0.0000
N[51] = 0.0000
N[52] = 0.0000
N[53] = 0.0000
N[54] = 0.0000
N[55] = 0.0000
N[56] = 0.0000
N[57] = 0.0000
N[58] = 0.0000
N[59] = 0.0000
N[60] = 0.0000
N[61] = 0.0000
N[62] = 0.0000
N[63] = 0.0000
N[64] = 0.0000
N[65] = 0.0000
N[66] = 0.0000
N[67] = 0.0000
N[68] = 0.0000
N[69] = 0.0000
N[70] = 0.0000
N[71] = 0.0000
N[72] = 0.0000
N[73] = 0.0000
N[74] = 0.0000
N[75] = 0.0000
N[76] = 0.0000
N[77] = 0.0000
N[78] = 0.0000
N[79] = 0.0000
N[80] = 0.0000
N[81] = 0.0000
N[82] = 0.0000
N[83] = 0.0000
N[84] = 0.0000
N[85] = 0.0000
N[86] = 0.0000
N[87] = 0.0000
N[88] = 0.0000
N[89] = 0.0000
N[90] = 0.0000
N[91] = 0.0000
N[92] = 0.0000
N[93] = 0.0000
N[94] = 0.0000
N[95] = 0.0000
N[96] = 0.0000
N[97] = 0.0000
N[98] = 0.0000
N[99] = 0.0000
Explanation
For , . Repeated halving gives , , , and . The process continues through index , and every value is printed with four digits after the decimal point.