Infer the Number of Elements with sizeof

Source: Understanding and Using C Pointers

Version: Phuoc Hung OJ Extended

Problem Statement

While $a$ is still an array object in the same scope, its element count can be computed as

$$\frac{\operatorname{sizeof}(a)}{\operatorname{sizeof}(a[0])}.$$

Suppose sizeof(a) is $B$ bytes and sizeof(a[0]) is $E$ bytes. It is guaranteed that $B$ is divisible by $E$. Compute the number of elements.

Input

One line contains two positive integers $B$ and $E$: the size in bytes of the whole array and of one element.

Output

Print the integer $B/E$.

Subtasks

Subtask 1 (20 points): $E=1$, $1\le B\le100$.

Subtask 2 (30 points): $E\in\{2,4,8\}$, $1\le B/E\le10^4$.

Subtask 3 (50 points): $1\le E\le10^6$, $1\le B\le10^{18}$, and $E$ divides $B$.

Examples

Input

80 8

Output

10

Explanation

Here $B=80$ and $E=8$, so

$$80/8=10.$$

The quotient is the number of array elements.